What is sqrt(\sqrt{16-x^2)} ?

The solution to sqrt(\sqrt{16-x^2)} is \sqrt[4]{-x^2+16}

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simplify sqrt(\sqrt{16-x^2)}

simplify

16 - x^{2}

Solution steps

16 - x^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((16 - x^{2})^{\frac{1}{2}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (16 - x^{2})^{\frac{1}{2} \cdot \frac{1}{2}}

\frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}

= (16 - x^{2})^{\frac{1}{4}}

(2 x^{3}) (5 x^{5})

e^{- r \cdot (\frac{1}{2})}

0.9 x 1 0^{- 5}

34.6 \cdot 1 0^{- 9}

- 20 e^{- 2 \cdot 1}

What is sqrt(\sqrt{16-x^2)} ?
The solution to sqrt(\sqrt{16-x^2)} is \sqrt[4]{-x^2+16}