What is sqrt(2^{\sqrt{2^{\sqrt{2)}}}} ?

The solution to sqrt(2^{\sqrt{2^{\sqrt{2)}}}} is 2^{(sqrt(2^{\sqrt{2)}})/2}

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simplify sqrt(2^{\sqrt{2^{\sqrt{2)}}}}

simplify

2^{2^{2}}

2^{\frac{2 ^{2}}{2}}

Decimal Notation

1.76083 \dots

Solution steps

2^{2^{2}}

Apply radical rule:

a = a^{\frac{1}{2}}

= (2^{2^{2}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{2^{2} \frac{1}{2}}

2^{2} \frac{1}{2} = \frac{2 ^{2}}{2}

= 2^{\frac{2 ^{2}}{2}}

x + 1 \cdot 3 - x

(π)^{- \frac{1}{3}}

(z^{\frac{4 ^{\circ}}{2}})^{4}

P^{1} (3, - 6) y P^{2} (5, 8)

What is sqrt(2^{\sqrt{2^{\sqrt{2)}}}} ?
The solution to sqrt(2^{\sqrt{2^{\sqrt{2)}}}} is 2^{(sqrt(2^{\sqrt{2)}})/2}