What is factor 16x^8-81y^4 ?

The solution to factor 16x^8-81y^4 is (4x^4+9y^2)(2x^2+3y)(2x^2-3y)

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factor 16x^8-81y^4

factor

16 x^{8} - 81 y^{4}

(4 x^{4} + 9 y^{2}) (2 x^{2} + 3 y) (2 x^{2} - 3 y)

Solution steps

16 x^{8} - 81 y^{4}

16 x^{8} = (4 x^{4})^{2}

81 y^{4} = (9 y^{2})^{2}

= (4 x^{4})^{2} - (9 y^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 x^{4})^{2} - (9 y^{2})^{2} = (4 x^{4} + 9 y^{2}) (4 x^{4} - 9 y^{2})

= (4 x^{4} + 9 y^{2}) (4 x^{4} - 9 y^{2})

Factor

4 x^{4} - 9 y^{2} : (2 x^{2} + 3 y) (2 x^{2} - 3 y)

= (4 x^{4} + 9 y^{2}) (2 x^{2} + 3 y) (2 x^{2} - 3 y)

4 x^{2} = 0

\frac{9}{3}

S = 72 2 (102.04)

\frac{1}{3} (- 9)

13

What is factor 16x^8-81y^4 ?
The solution to factor 16x^8-81y^4 is (4x^4+9y^2)(2x^2+3y)(2x^2-3y)