What is (1.1*10^{-1})(4x10^{-2}) ?

The solution to (1.1*10^{-1})(4x10^{-2}) is (0.44x)/(100)

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simplify (1.1*10^{-1})(4x10^{-2})

simplify

(1.1 \cdot 1 0^{- 1}) (4 x 1 0^{- 2})

\frac{0.44 x}{100}

Solution steps

(1.1 \cdot 1 0^{- 1}) (4 x \cdot 1 0^{- 2})

Simplify

1.1 \cdot 1 0^{- 1} : 0.11

= 0.11 \cdot 4 x \cdot 1 0^{- 2}

1 0^{- 2} = \frac{1}{100}

= 0.11 \cdot 4 x \frac{1}{100}

Multiply the numbers:

0.11 \cdot 4 = 0.44

= 0.44 x \frac{1}{100}

= \frac{1}{100} \cdot 0.44 x

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 0.44 x}{100}

Multiply the numbers:

1 \cdot 0.44 = 0.44

= \frac{0.44 x}{100}

e^{- 4891294749}

(0.5) e^{- 0.06 t}

1.76 (1 0^{- 6})

1.08 \cdot 1 0^{- 3} \cdot 34.014

2 e^{2 t} \cdot t e^{25}

What is (1.1*10^{-1})(4x10^{-2}) ?
The solution to (1.1*10^{-1})(4x10^{-2}) is (0.44x)/(100)