What is (e^{64/7})^{ln(8)-1} ?

The solution to (e^{64/7})^{ln(8)-1} is e^{(64(3ln(2)-1))/7}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (e^{64/7})^{ln(8)-1}

simplify

(e^{\frac{64}{7}})^{l n (8) - 1}

e^{\frac{64 ( 3 l n ( 2 ) - 1 )}{7}}

Decimal Notation

19325.48189 \dots

Solution steps

(e^{\frac{64}{7}})^{l n (8) - 1}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= e^{\frac{64}{7} (l n (8) - 1)}

\frac{64}{7} (ln (8) - 1) = \frac{64 ( 3 ln ( 2 ) - 1 )}{7}

= e^{\frac{64 ( 3 l n ( 2 ) - 1 )}{7}}

0.96 \cdot 1 0^{- 1}

(x y^{2} z^{3}) (x^{3} y^{2} z)

(7 a^{2} \cdot b e^{6}) e^{4}

(4 x^{5}) (5 x^{2})

6 x^{3} 3 x

What is (e^{64/7})^{ln(8)-1} ?
The solution to (e^{64/7})^{ln(8)-1} is e^{(64(3ln(2)-1))/7}