What are the solutions to the equation (x+3)(x-9)=0 ?

The solutions to the equation (x+3)(x-9)=0 are x=-3,x=9

Find the zeros of (x+3)(x-9)=0

The zeros of (x+3)(x-9)=0 are x=-3,x=9

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(x + 3) (x - 9) = 0

x = - 3, x = 9

Solution steps

(x + 3) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 9 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 9 = 0 : x = 9

The solutions to the quadratic equation are:

x = - 3, x = 9

5 x^{2} - 55 = 0

- \frac{1}{( 3 + 4 ) ^{2}}

49 j^{2} - 84 j + 36

r^{2} + 12 r + 37 = 0

5 x^{2} + 9 x = 4

What are the solutions to the equation (x+3)(x-9)=0 ?
The solutions to the equation (x+3)(x-9)=0 are x=-3,x=9
Find the zeros of (x+3)(x-9)=0
The zeros of (x+3)(x-9)=0 are x=-3,x=9