What is ,((4p^2)/(3p^4))^{-3} ?

The solution to ,((4p^2)/(3p^4))^{-3} is (27p^6)/(64)

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simplify ,((4p^2)/(3p^4))^{-3}

simplify

(\frac{4 p ^{2}}{3 p ^{4}})^{- 3}

\frac{27 p ^{6}}{64}

Solution steps

(\frac{4 p ^{2}}{3 p ^{4}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{4 p ^{2}}{3 p ^{4}})^{- 3} = \frac{1}{( \frac{4 p ^{2}}{3 p ^{4}} ) ^{3}}

= \frac{1}{( \frac{4 p ^{2}}{3 p ^{4}} ) ^{3}}

Simplify

(\frac{4 p ^{2}}{3 p ^{4}})^{3} : \frac{64}{27 p ^{6}}

= \frac{1}{\frac{64}{27 p ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{27 p ^{6}}{64}

2.11 \cdot 1 0^{- 4}

20 \cdot 6.2 5^{- 0.5}

e^{- 2 s i n (x)}

8.23 \cdot 1 0^{- 3} \cdot 5

(100) e^{- (0.03 1^{- 1}) (20)}

What is ,((4p^2)/(3p^4))^{-3} ?
The solution to ,((4p^2)/(3p^4))^{-3} is (27p^6)/(64)