What is k^2(k+2)^2(k^2+2k) ?

The solution to k^2(k+2)^2(k^2+2k) is k^2(k+2)^2(k^2+2k)

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simplify k^2(k+2)^2(k^2+2k)

simplify

k^{2} (k + 2)^{2} (k^{2} + 2 k)

k^{2} (k + 2)^{2} (k^{2} + 2 k)

Solution steps

k^{2} (k + 2)^{2} (k^{2} + 2 k)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

k^{2} (k + 2)^{2} = (k (k + 2))^{2}

= (k (k + 2))^{2} (k^{2} + 2 k)

(k (k + 2))^{2} = k^{2} (k + 2)^{2}

= k^{2} (k + 2)^{2} (k^{2} + 2 k)

0.045 e^{(- 0.0693)}

5 e^{- 1.3}

96 \cdot e^{- (0.0017) (20)}

(4.6 x 1 0^{- 7}) (7.13 x 1 0^{9})

- e^{- 0^{4}}

What is k^2(k+2)^2(k^2+2k) ?
The solution to k^2(k+2)^2(k^2+2k) is k^2(k+2)^2(k^2+2k)