What are the solutions to the equation x^{(2)}+2x-3=0 ?

The solutions to the equation x^{(2)}+2x-3=0 are x=1,x=-3

Find the zeros of x^{(2)}+2x-3=0

The zeros of x^{(2)}+2x-3=0 are x=1,x=-3

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x^{(2)} + 2 x - 3 = 0

x = 1, x = - 3

Solution steps

x^{(2)} + 2 x - 3 = 0

Refine

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

x (x^{\frac{1}{3}})

2 \cdot \frac{2}{2}

(- 125)^{- \frac{2}{3}}

6 - 2 x

y, x^{2} + y^{2} - 6 x - 6 y + 18 = 0

What are the solutions to the equation x^{(2)}+2x-3=0 ?
The solutions to the equation x^{(2)}+2x-3=0 are x=1,x=-3
Find the zeros of x^{(2)}+2x-3=0
The zeros of x^{(2)}+2x-3=0 are x=1,x=-3