What is ((x^3-3x^2+3x-1)y^3)y ?

The solution to ((x^3-3x^2+3x-1)y^3)y is y^4(x^3-3x^2+3x-1)

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simplify ((x^3-3x^2+3x-1)y^3)y

simplify

((x^{3} - 3 x^{2} + 3 x - 1) y^{3}) y

y^{4} (x^{3} - 3 x^{2} + 3 x - 1)

Solution steps

((x^{3} - 3 x^{2} + 3 x - 1) y^{3}) y

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{3} y = y^{3 + 1}

= (x^{3} - 3 x^{2} + 3 x - 1) y^{3 + 1}

Add the numbers:

3 + 1 = 4

= (x^{3} - 3 x^{2} + 3 x - 1) y^{4}

30. 1^{- 6}

3.80405 \cdot 1 0^{- 3}

50 \cdot e^{- 30 k}

(5 x^{7} y^{4}) (2 x^{3} y^{5})

What is ((x^3-3x^2+3x-1)y^3)y ?
The solution to ((x^3-3x^2+3x-1)y^3)y is y^4(x^3-3x^2+3x-1)