What is (ae^{-at}sin(θ)(t))u(t) ?

The solution to (ae^{-at}sin(θ)(t))u(t) is ae^{-at}t^2usin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (ae^{-at}sin(θ)(t))u(t)

simplify

(a e^{- a t} sin (θ) (t)) u (t)

a e^{- a t} t^{2} u sin (θ)

Solution steps

(a e^{- a t} sin (θ) (t)) u (t)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

tt = t^{1 + 1}

= a e^{- a t} sin (θ) u t^{1 + 1}

Add the numbers:

1 + 1 = 2

= a e^{- a t} sin (θ) u t^{2}

- 10 \cdot e^{- 3 \cdot 100}

e^{- 3 x} (3 x - 1)

32.2 \cdot 1 0^{- 12} \cdot 6.096

3.33 \cdot 1 0^{- 5}

29 4^{^{'}}

What is (ae^{-at}sin(θ)(t))u(t) ?
The solution to (ae^{-at}sin(θ)(t))u(t) is ae^{-at}t^2usin(θ)