What is 3te^{-2t}cos(a)lphat ?

The solution to 3te^{-2t}cos(a)lphat is 3le^{-2t}t^2aphcos(a)

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simplify 3te^{-2t}cos(a)lphat

simplify

3 t e^{- 2 t} cos (a) lp ha t

3 l e^{- 2 t} t^{2} a p h cos (a)

Solution steps

3 t e^{- 2 t} cos (a) lp ha t

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

tt = t^{1 + 1}

= 3 e^{- 2 t} cos (a) lp ha t^{1 + 1}

Add the numbers:

1 + 1 = 2

= 3 e^{- 2 t} cos (a) lp ha t^{2}

2.4 \cdot 1 0^{- 17} \cdot 9.8

\frac{e ^{1}}{e ^{- 9}}

(4 \cdot 1 0^{8}) (7 \cdot 1 0^{7})

(8 a) \frac{1}{3} x^{2} a b^{2}

2 5 e^{2}

What is 3te^{-2t}cos(a)lphat ?
The solution to 3te^{-2t}cos(a)lphat is 3le^{-2t}t^2aphcos(a)