What are the solutions to the equation 3(x-10)^2=48 ?

The solutions to the equation 3(x-10)^2=48 are x=14,x=6

Find the zeros of 3(x-10)^2=48

The zeros of 3(x-10)^2=48 are x=14,x=6

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3 (x - 10)^{2} = 48

x = 14, x = 6

Solution steps

3 (x - 10)^{2} = 48

Divide both sides by

3

(x - 10)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 10 = 16 : x = 14

Solve

x - 10 = - 16 : x = 6

The solutions to the quadratic equation are:

x = 14, x = 6

- \frac{3}{4} + \frac{7}{8} - \frac{1}{10}

\frac{3 x - 2}{1 - x} \leq - 3

\frac{5 x - 2}{4} + \frac{13 - 2 x}{6} = 1 - \frac{1 + x}{12}

x^{2} + 5.02 \cdot 1 0^{- 2} x - 1.8 \cdot 1 0^{- 5} = 0

- 10 - 4

What are the solutions to the equation 3(x-10)^2=48 ?
The solutions to the equation 3(x-10)^2=48 are x=14,x=6
Find the zeros of 3(x-10)^2=48
The zeros of 3(x-10)^2=48 are x=14,x=6