What is (8X^{10}-2)(4X^{104})2X^{101} ?

The solution to (8X^{10}-2)(4X^{104})2X^{101} is 8X^{205}(8X^{10}-2)

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simplify (8X^{10}-2)(4X^{104})2X^{101}

simplify

(8 X^{10} - 2) (4 X^{104}) 2 X^{101}

8 X^{205} (8 X^{10} - 2)

Solution steps

(8 X^{10} - 2) (4 X^{104}) \cdot 2 X^{101}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

X^{104} X^{101} = X^{104 + 101}

= (8 X^{10} - 2) \cdot 4 \cdot 2 X^{104 + 101}

Add the numbers:

104 + 101 = 205

= (8 X^{10} - 2) \cdot 4 \cdot 2 X^{205}

Multiply the numbers:

4 \cdot 2 = 8

= 8 X^{205} (8 X^{10} - 2)

cos (a t) e^{(- s t)}

8.66 \cdot 1 0^{- 6} \cdot 20

(4 x 1 0^{6}) x (5 x 1 0^{5})

- e^{- \frac{5}{6}} \cdot (- 60)

3 a^{2} e^{4} \cdot 2 a^{3} e^{2}

What is (8X^{10}-2)(4X^{104})2X^{101} ?
The solution to (8X^{10}-2)(4X^{104})2X^{101} is 8X^{205}(8X^{10}-2)