What is (\sqrt[3]{6-x})^{1/3} ?

The solution to (\sqrt[3]{6-x})^{1/3} is (-x+6)^{1/9}

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simplify (\sqrt[3]{6-x})^{1/3}

simplify

(- x + 6)^{\frac{1}{9}}

Solution steps

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (6 - x)^{\frac{1}{3} \cdot \frac{1}{3}}

\frac{1}{3} \cdot \frac{1}{3} = \frac{1}{9}

= (6 - x)^{\frac{1}{9}}

= (- x + 6)^{\frac{1}{9}}

5 r^{2} s^{2} (- 3 s + 2 r + 5)

- 0.72 e^{- 0.6 (6.9)}

18 \cdot e^{- 9}

e^{- a t} e^{(a + b)}

(10 - 3) \cdot 1 0^{- 6} \cdot 0.064

What is (\sqrt[3]{6-x})^{1/3} ?
The solution to (\sqrt[3]{6-x})^{1/3} is (-x+6)^{1/9}