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Popular >

simplify g^{-1}(7+x+e^x)

Solution

simplify

g^{- 1} (7 + x + e^{x})

Solution

\frac{x + e ^{x} + 7}{g}

Solution steps

g^{- 1} (7 + x + e^{x})

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{g} (x + e^{x} + 7)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 7 + x + e ^{x} )}{g}

1 \cdot (7 + x + e^{x}) = 7 + x + e^{x}

= \frac{7 + x + e ^{x}}{g}

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Frequently Asked Questions (FAQ)

What is g^{-1}(7+x+e^x) ?
The solution to g^{-1}(7+x+e^x) is (x+e^x+7)/g