What are the solutions to the equation -4x^2-8x+192=0 ?

The solutions to the equation -4x^2-8x+192=0 are x=-8,x=6

Find the zeros of -4x^2-8x+192=0

The zeros of -4x^2-8x+192=0 are x=-8,x=6

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- 4 x^{2} - 8 x + 192 = 0

x = - 8, x = 6

Solution steps

- 4 x^{2} - 8 x + 192 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 4 ) \cdot 192}{2 ( - 4 )}

(- 8)^{2} - 4 (- 4) \cdot 192 = 56

x_{1, 2} = \frac{- ( - 8 ) \pm 56}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 56}{2 ( - 4 )}, x_{2} = \frac{- ( - 8 ) - 56}{2 ( - 4 )}

x = \frac{- ( - 8 ) + 56}{2 ( - 4 )} : - 8

x = \frac{- ( - 8 ) - 56}{2 ( - 4 )} : 6

The solutions to the quadratic equation are:

x = - 8, x = 6

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10 x^{2} - 3 x - 1 = 0

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- \frac{π}{3} + 2 π

What are the solutions to the equation -4x^2-8x+192=0 ?
The solutions to the equation -4x^2-8x+192=0 are x=-8,x=6
Find the zeros of -4x^2-8x+192=0
The zeros of -4x^2-8x+192=0 are x=-8,x=6