What is f^{-1(x)=(2-x^2)/7} ?

The solution to f^{-1(x)=(2-x^2)/7} is 1/(f^{1=\frac{-x^2+2){7}x}}

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simplify f^{-1(x)=(2-x^2)/7}

simplify

f^{- 1 (x) = \frac{2 - x ^{2}}{7}}

\frac{1}{f ^{1 = \frac{- x ^{2} + 2}{7} x}}

Solution steps

f^{- 1 \cdot (x) = \frac{2 - x ^{2}}{7}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{f ^{1 \cdot x = \frac{- x ^{2} + 2}{7}}}

(2 k)^{3}

0.001 \cdot e^{- 1.2}

\frac{( 0.01 c ) ^{2}}{c ^{2}}

\frac{e ^{x}}{e ^{5 + x}}

What is f^{-1(x)=(2-x^2)/7} ?
The solution to f^{-1(x)=(2-x^2)/7} is 1/(f^{1=\frac{-x^2+2){7}x}}