What is f(-2x+1)\circ f(5x^2-125) ?

The solution to f(-2x+1)\circ f(5x^2-125) is \circ f^2(-2x+1)(5x^2-125)

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simplify f(-2x+1)\circ f(5x^2-125)

simplify

f (- 2 x + 1) \circ f (5 x^{2} - 125)

\circ f^{2} (- 2 x + 1) (5 x^{2} - 125)

Solution steps

f (- 2 x + 1) \circ f (5 x^{2} - 125)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ff = f^{1 + 1}

= (- 2 x + 1) \circ f^{1 + 1} (5 x^{2} - 125)

Add the numbers:

1 + 1 = 2

= (- 2 x + 1) \circ f^{2} (5 x^{2} - 125)

e^{- r x} e^{r x}

8.86 \cdot 1 0^{- 3}

7 e^{- 0.93}

2 π (5) (2.2 \cdot 1 0^{- 9})

(0)^{6} \cdot e^{- (0)^{2}}

What is f(-2x+1)\circ f(5x^2-125) ?
The solution to f(-2x+1)\circ f(5x^2-125) is \circ f^2(-2x+1)(5x^2-125)