What is (1.67x10^{-27})(9.41x10^{-31}) ?

The solution to (1.67x10^{-27})(9.41x10^{-31}) is (15.7147x^2)/(10^{58)}

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simplify (1.67x10^{-27})(9.41x10^{-31})

simplify

(1.67 x 1 0^{- 27}) (9.41 x 1 0^{- 31})

\frac{15.7147 x ^{2}}{1 0 ^{58}}

Solution steps

(1.67 x \cdot 1 0^{- 27}) (9.41 x \cdot 1 0^{- 31})

Simplify

1.67 x \cdot 1 0^{- 27} : \frac{1.67 x}{1 0 ^{27}}

= \frac{1.67 x}{1 0 ^{27}} \cdot 9.41 x \cdot 1 0^{- 31}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 31} = \frac{1}{1 0 ^{31}}

= \frac{1.67 x}{1 0 ^{27}} \cdot 9.41 x \frac{1}{1 0 ^{31}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1.67 x \cdot 9.41 x \cdot 1}{1 0 ^{27} \cdot 1 0 ^{31}}

Simplify

1.67 x \cdot 9.41 x \cdot 1 : 15.7147 x^{2}

= \frac{15.7147 x ^{2}}{1 0 ^{27} \cdot 1 0 ^{31}}

1 0^{27} \cdot 1 0^{31} = 1 0^{58}

= \frac{15.7147 x ^{2}}{1 0 ^{58}}

x^{2} e^{- s i n h (x)}

\frac{π}{2} (3.16 \cdot 1 0^{- 4})

e^{- 1000} \cdot e^{- 1000}

15. 1^{20} (1.6 x 1 0^{- 19})

1131105.39 \cdot 1 0^{- 6}

What is (1.67x10^{-27})(9.41x10^{-31}) ?
The solution to (1.67x10^{-27})(9.41x10^{-31}) is (15.7147x^2)/(10^{58)}