What is (-1)^4(x^2-8x+12)e^{-x} ?

The solution to (-1)^4(x^2-8x+12)e^{-x} is (x^2-8x+12)/(e^x)

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simplify (-1)^4(x^2-8x+12)e^{-x}

simplify

(- 1)^{4} (x^{2} - 8 x + 12) e^{- x}

\frac{x ^{2} - 8 x + 12}{e ^{x}}

Solution steps

(- 1)^{4} (x^{2} - 8 x + 12) e^{- x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= (- 1)^{4} \frac{1}{e ^{x}} (x^{2} - 8 x + 12)

(- 1)^{4} = 1

= 1 \cdot \frac{1}{e ^{x}} (x^{2} - 8 x + 12)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 1 \cdot \frac{1 \cdot ( x ^{2} - 8 x + 12 )}{e ^{x}}

1 \cdot (x^{2} - 8 x + 12) = x^{2} - 8 x + 12

= 1 \cdot \frac{x ^{2} - 8 x + 12}{e ^{x}}

Multiply:

1 \cdot \frac{x ^{2} - 8 x + 12}{e ^{x}} = \frac{x ^{2} - 8 x + 12}{e ^{x}}

= \frac{x ^{2} - 8 x + 12}{e ^{x}}

(2 a + 4)^{3} (2 a - 4)^{3}

(31 a^{5} b^{2}) (7 a^{2} b^{3} c)

(1.23 x 1 0^{3}) (6.4 x 1 0^{2})

(2 x^{2} y^{3}) (x^{3} + x^{2})^{2}

\frac{8 - x}{x - 5}

What is (-1)^4(x^2-8x+12)e^{-x} ?
The solution to (-1)^4(x^2-8x+12)e^{-x} is (x^2-8x+12)/(e^x)