What is 5e^{40j}*3e^{-20j} ?

The solution to 5e^{40j}*3e^{-20j} is 15e^{20j}

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simplify 5e^{40j}*3e^{-20j}

simplify

5 e^{40 j} \cdot 3 e^{- 20 j}

15 e^{20 j}

Solution steps

5 e^{40 j} \cdot 3 e^{- 20 j}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{40 j} e^{- 20 j} = e^{40 j - 20 j}

= 5 \cdot 3 e^{40 j - 20 j}

Add similar elements:

40 j - 20 j = 20 j

= 5 \cdot 3 e^{20 j}

Multiply the numbers:

5 \cdot 3 = 15

= 15 e^{20 j}

e^{- 4} \cdot \frac{4 ^{4}}{4 !}

- 5 x^{3} y \cdot (x y^{2})

9.62 \cdot 1 0^{- 3}

1000000 (1 - 0.24)^{- 3}

(1 + x)^{3} (1 - x)^{3}