What is (3.1)(1.6*10^{-19}) ?

The solution to (3.1)(1.6*10^{-19}) is (31)/(5^{19)*3276800}

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simplify (3.1)(1.6*10^{-19})

simplify

(3.1) (1.6 \cdot 1 0^{- 19})

\frac{31}{5 ^{19} \cdot 3276800}

Decimal Notation

4.96 E - 19

Solution steps

(3.1) (1.6 \cdot 1 0^{- 19})

Apply rule:

(a) = a

(3.1) = 3.1

= 3.1 \cdot 1.6 \cdot 1 0^{- 19}

Multiply the numbers:

3.1 \cdot 1.6 = 4.96

= 4.96 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 4.96

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 4.96

\frac{1}{1 0 ^{19}} \cdot 4.96 = \frac{4.96}{1 0 ^{19}}

= \frac{4.96}{1 0 ^{19}}

\frac{4.96}{1 0 ^{19}} = \frac{496}{100 \cdot 1 0 ^{19}}

= \frac{496}{100 \cdot 1 0 ^{19}}

Factor the number:

496 = 4 \cdot 124

= \frac{4 \cdot 124}{100 \cdot 1 0 ^{19}}

Factor the number:

100 = 4 \cdot 25

= \frac{4 \cdot 124}{4 \cdot 25 \cdot 1 0 ^{19}}

Cancel the common factor:

4

= \frac{124}{25 \cdot 1 0 ^{19}}

Factor

124 : 2^{2} \cdot 31

= \frac{2 ^{2} \cdot 31}{25 \cdot 1 0 ^{19}}

Factor

1 0^{19} : 2^{19} \cdot 5^{19}

= \frac{2 ^{2} \cdot 31}{25 \cdot 2 ^{19} \cdot 5 ^{19}}

\frac{2 ^{2}}{2 ^{19}} = \frac{1}{2 ^{17}}

= \frac{31}{25 \cdot 2 ^{17} \cdot 5 ^{19}}

25 \cdot 2^{17} \cdot 5^{19} = 5^{19} \cdot 3276800

= \frac{31}{5 ^{19} \cdot 3276800}

4 \cdot 7.23 \cdot 1 0^{- 3}

8.32 \cdot 1 0^{- 2}

k 2 (82)

2.5 x 1 0^{- 6}

(4 a^{2}) (4 b^{2})

What is (3.1)(1.6*10^{-19}) ?
The solution to (3.1)(1.6*10^{-19}) is (31)/(5^{19)*3276800}