What is ((-1)/2+e^{2x})^{-1} ?

The solution to ((-1)/2+e^{2x})^{-1} is 2/(2e^{2x)-1}

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simplify ((-1)/2+e^{2x})^{-1}

simplify

(\frac{- 1}{2} + e^{2 x})^{- 1}

\frac{2}{2 e ^{2 x} - 1}

Solution steps

(\frac{- 1}{2} + e^{2 x})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( \frac{- 1}{2} + e ^{2 x} )}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= \frac{1}{- \frac{1}{2} + e ^{2 x}}

Join

- \frac{1}{2} + e^{2 x} : \frac{- 1 + 2 e ^{2 x}}{2}

= \frac{1}{\frac{- 1 + 2 e ^{2 x}}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{- 1 + e ^{2 x} \cdot 2}

(c^{4} d^{4}) \frac{1}{3}

5.9 \cdot 1 0^{- 1}

15 e^{- 0.001 x}

- e^{y} \cdot (e^{- y})^{2}

(3.14 x 1 0^{3}) x (7.8 x 1 0^{5})

What is ((-1)/2+e^{2x})^{-1} ?
The solution to ((-1)/2+e^{2x})^{-1} is 2/(2e^{2x)-1}