What is (ML^{-3})(L^2t^{-2}) ?

The solution to (ML^{-3})(L^2t^{-2}) is M/(Lt^2)

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simplify (ML^{-3})(L^2t^{-2})

simplify

(M L^{- 3}) (L^{2} t^{- 2})

\frac{M}{L t ^{2}}

Solution steps

(M L^{- 3}) (L^{2} t^{- 2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

L^{- 3} L^{2} = L^{- 3 + 2}

= M L^{- 3 + 2} t^{- 2}

Add/Subtract the numbers:

- 3 + 2 = - 1

= M L^{- 1} t^{- 2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

L^{- 1} = \frac{1}{L}

= \frac{1}{L} M t^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

t^{- 2} = \frac{1}{t ^{2}}

= \frac{1}{L} \cdot \frac{1}{t ^{2}} M

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 1 \cdot M}{L t ^{2}}

Multiply:

1 \cdot 1 \cdot M = M

= \frac{M}{L t ^{2}}

[(- 24)^{5}]^{7}

8^{- 5} 0. 8^{9}

- 2 - 5 - 9

- e^{- x} \cdot e^{x}