What are the solutions to the equation r^2+6r+4=0 ?

The solutions to the equation r^2+6r+4=0 are r=-3+sqrt(5),r=-3-sqrt(5)

Find the zeros of r^2+6r+4=0

The zeros of r^2+6r+4=0 are r=-3+sqrt(5),r=-3-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 6 r + 4 = 0

r = - 3 + 5, r = - 3 - 5

Solution steps

r^{2} + 6 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 4 = 25

r_{1, 2} = \frac{- 6 \pm 2 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 6 + 2 5}{2 \cdot 1}, r_{2} = \frac{- 6 - 2 5}{2 \cdot 1}

r = \frac{- 6 + 2 5}{2 \cdot 1} : - 3 + 5

r = \frac{- 6 - 2 5}{2 \cdot 1} : - 3 - 5

The solutions to the quadratic equation are:

r = - 3 + 5, r = - 3 - 5

\frac{6}{2 ^{2}}

\frac{4 ^{- 2}}{4 ^{- 3}}

- x^{2} - 15 x - 54

64 x^{6} - 125 y^{6}

\frac{8 - 7 i}{8 + i}

What are the solutions to the equation r^2+6r+4=0 ?
The solutions to the equation r^2+6r+4=0 are r=-3+sqrt(5),r=-3-sqrt(5)
Find the zeros of r^2+6r+4=0
The zeros of r^2+6r+4=0 are r=-3+sqrt(5),r=-3-sqrt(5)