What is 0.5(5KL^{-1/2}) ?

The solution to 0.5(5KL^{-1/2}) is (2.5K)/(L^{1/2)}

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simplify 0.5(5KL^{-1/2})

simplify

0.5 (5 K L^{- \frac{1}{2}})

\frac{2.5 K}{L ^{\frac{1}{2}}}

Solution steps

0.5 (5 K L^{- \frac{1}{2}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

L^{- \frac{1}{2}} = \frac{1}{L ^{\frac{1}{2}}}

= 0.5 \cdot 5 K \frac{1}{L ^{\frac{1}{2}}}

Simplify

5 K \frac{1}{L ^{\frac{1}{2}}} : \frac{5 K}{L ^{\frac{1}{2}}}

= 0.5 \cdot \frac{5 K}{L ^{\frac{1}{2}}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{0.5 \cdot 5 K}{L ^{\frac{1}{2}}}

Multiply the numbers:

0.5 \cdot 5 = 2.5

= \frac{2.5 K}{L ^{\frac{1}{2}}}

120 e^{- 0.231 x^{12}}

x \cdot (6 e^{- x^{2}})

9.11 e^{- 31}

- 28.56 x 1 0^{- 2}

\frac{5 ^{x}}{6 ^{x}}