What are the solutions to the equation x^2+6x+112=0 ?

The solutions to the equation x^2+6x+112=0 are x=-3+sqrt(103)i,x=-3-sqrt(103)i

Find the zeros of x^2+6x+112=0

The zeros of x^2+6x+112=0 are x=-3+sqrt(103)i,x=-3-sqrt(103)i

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x^{2} + 6 x + 112 = 0

x = - 3 + 103 i, x = - 3 - 103 i

Solution steps

x^{2} + 6 x + 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 112}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 112 : 2103 i

x_{1, 2} = \frac{- 6 \pm 2 103 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 103 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 103 i}{2 \cdot 1}

x = \frac{- 6 + 2 103 i}{2 \cdot 1} : - 3 + 103 i

x = \frac{- 6 - 2 103 i}{2 \cdot 1} : - 3 - 103 i

The solutions to the quadratic equation are:

x = - 3 + 103 i, x = - 3 - 103 i

∣ x - 3 ∣ \geq 2

150 = - 9 x - 6 x

8 - 10

18 x^{2} - 24 x + 5 = 0

(- \frac{1}{2 6 - x})^{2}

What are the solutions to the equation x^2+6x+112=0 ?
The solutions to the equation x^2+6x+112=0 are x=-3+sqrt(103)i,x=-3-sqrt(103)i
Find the zeros of x^2+6x+112=0
The zeros of x^2+6x+112=0 are x=-3+sqrt(103)i,x=-3-sqrt(103)i