What are the solutions to the equation 0=-16x^2+4x ?

The solutions to the equation 0=-16x^2+4x are x=0,x= 1/4

Find the zeros of 0=-16x^2+4x

The zeros of 0=-16x^2+4x are x=0,x= 1/4

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0 = - 16 x^{2} + 4 x

x = 0, x = \frac{1}{4}

Solution steps

0 = - 16 x^{2} + 4 x

Switch sides

- 16 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

4^{2} - 4 (- 16) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 16 )}, x_{2} = \frac{- 4 - 4}{2 ( - 16 )}

x = \frac{- 4 + 4}{2 ( - 16 )} : 0

x = \frac{- 4 - 4}{2 ( - 16 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{4}

x + 9 = 2 x + 6

∣ x + 1 ∣ \geq 3

\frac{3}{∣ 5 - 2 x ∣} \leq 1

0.3 (z - 4) = 15

4 (- \frac{3}{8})

What are the solutions to the equation 0=-16x^2+4x ?
The solutions to the equation 0=-16x^2+4x are x=0,x= 1/4
Find the zeros of 0=-16x^2+4x
The zeros of 0=-16x^2+4x are x=0,x= 1/4