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Popular >

simplify 2x'2x^2x^2x

Solution

simplify

2 x^{'} 2 x^{2} x^{2} x

Solution

4 x^{5} x'

Solution steps

2 x^{'} 2 x^{2} x^{2} x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= x^{^{'}} 2^{1 + 1} x^{2} x^{2} x

Add the numbers:

1 + 1 = 2

= x^{^{'}} 2^{2} x^{2} x^{2} x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2} x^{2} x = x^{2 + 2 + 1}

= x^{^{'}} 2^{2} x^{2 + 2 + 1}

Add the numbers:

2 + 2 + 1 = 5

= x^{^{'}} 2^{2} x^{5}

2^{2} = 4

= 4 x^{5} x^{^{'}}

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Frequently Asked Questions (FAQ)

What is 2x'2x^2x^2x ?
The solution to 2x'2x^2x^2x is 4x^5x'