What are the solutions to the equation 4x-x^2=x ?

The solutions to the equation 4x-x^2=x are x=0,x=3

Find the zeros of 4x-x^2=x

The zeros of 4x-x^2=x are x=0,x=3

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4 x - x^{2} = x

x = 0, x = 3

Solution steps

4 x - x^{2} = x

Move

x

to the left side

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

455

\frac{800000}{299792458} \cdot 100

(5^{2})^{2}

5 = \frac{1}{3} x + 2

\frac{x + 6}{3} - x + 6 \geq \frac{x}{15}

What are the solutions to the equation 4x-x^2=x ?
The solutions to the equation 4x-x^2=x are x=0,x=3
Find the zeros of 4x-x^2=x
The zeros of 4x-x^2=x are x=0,x=3