What is 20(1+e^{10-t})^{-1} ?

The solution to 20(1+e^{10-t})^{-1} is (20)/(e^{-t+10)+1}

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simplify 20(1+e^{10-t})^{-1}

simplify

20 (1 + e^{10 - t})^{- 1}

\frac{20}{e ^{- t + 10} + 1}

Solution steps

20 (1 + e^{10 - t})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 20 \cdot \frac{1}{( e ^{- t + 10} + 1 )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 20}{1 + e ^{10 - t}}

Multiply the numbers:

1 \cdot 20 = 20

= \frac{20}{1 + e ^{- t + 10}}

2 t e^{- 0.5 t} \cdot d t

26 (226)

(2.47 \cdot 1 0^{- 4}) \cdot 235

What is 20(1+e^{10-t})^{-1} ?
The solution to 20(1+e^{10-t})^{-1} is (20)/(e^{-t+10)+1}