What are the solutions to the equation n^2=-18-9n ?

The solutions to the equation n^2=-18-9n are n=-3,n=-6

Find the zeros of n^2=-18-9n

The zeros of n^2=-18-9n are n=-3,n=-6

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n^{2} = - 18 - 9 n

n = - 3, n = - 6

Solution steps

n^{2} = - 18 - 9 n

Move

9 n

to the left side

n^{2} + 9 n = - 18

Move

18

to the left side

n^{2} + 9 n + 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

n_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 9 + 3}{2 \cdot 1}, n_{2} = \frac{- 9 - 3}{2 \cdot 1}

n = \frac{- 9 + 3}{2 \cdot 1} : - 3

n = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = - 3, n = - 6

3 x^{2} + 21 x - 24

\frac{2}{5} - \frac{1}{3}

3 s^{3} - 6 s

\frac{4.01}{4.01 - 4}

r^{2} - y^{2}

What are the solutions to the equation n^2=-18-9n ?
The solutions to the equation n^2=-18-9n are n=-3,n=-6
Find the zeros of n^2=-18-9n
The zeros of n^2=-18-9n are n=-3,n=-6