What is e^{-2t}sin^2(t)dx ?

The solution to e^{-2t}sin^2(t)dx is (sin^2(t)dx)/(e^{2t)}

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simplify e^{-2t}sin^2(t)dx

simplify

e^{- 2 t} sin^{2} (t) d x

\frac{sin ^{2} ( t ) d x}{e ^{2 t}}

Solution steps

e^{- 2 t} sin^{2} (t) d x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 t}} sin^{2} (t) d x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ^{2} ( t ) d x}{e ^{2 t}}

Multiply:

1 \cdot sin^{2} (t) = sin^{2} (t)

= \frac{sin ^{2} ( t ) d x}{e ^{2 t}}

(0)^{2} e^{- (\frac{10}{3})}

0.001 \cdot 2^{- 2}

11 (1 + e^{- x})^{- 1}

6 e^{- 200}

π \cdot 0.08 \cdot 10. 1^{- 2}

What is e^{-2t}sin^2(t)dx ?
The solution to e^{-2t}sin^2(t)dx is (sin^2(t)dx)/(e^{2t)}