What is f\circ gy^4g\circ 4f ?

The solution to f\circ gy^4g\circ 4f is 4\circ ^2f^2g^2y^4

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simplify f\circ gy^4g\circ 4f

simplify

f \circ g y^{4} g \circ 4 f

4 \circ^{2} f^{2} g^{2} y^{4}

Solution steps

f \circ g y^{4} g \circ 4 f

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

\circ \circ = \circ^{1 + 1}

= f g y^{4} g \circ^{1 + 1} \cdot 4 f

Add the numbers:

1 + 1 = 2

= f g y^{4} g \circ^{2} \cdot 4 f

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ff = f^{1 + 1}

= g y^{4} g \circ^{2} \cdot 4 f^{1 + 1}

Add the numbers:

1 + 1 = 2

= g y^{4} g \circ^{2} \cdot 4 f^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

gg = g^{1 + 1}

= y^{4} g^{1 + 1} \circ^{2} \cdot 4 f^{2}

Add the numbers:

1 + 1 = 2

= y^{4} g^{2} \circ^{2} \cdot 4 f^{2}

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What is f\circ gy^4g\circ 4f ?
The solution to f\circ gy^4g\circ 4f is 4\circ ^2f^2g^2y^4