What is (m+1)^2(m-1)^2(m+7) ?

The solution to (m+1)^2(m-1)^2(m+7) is (m+1)^2(m-1)^2(m+7)

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simplify (m+1)^2(m-1)^2(m+7)

simplify

(m + 1)^{2} (m - 1)^{2} (m + 7)

(m + 1)^{2} (m - 1)^{2} (m + 7)

Solution steps

(m + 1)^{2} (m - 1)^{2} (m + 7)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(m + 1)^{2} (m - 1)^{2} = ((m + 1) (m - 1))^{2}

= ((m + 1) (m - 1))^{2} (m + 7)

((m + 1) (m - 1))^{2} = (m + 1)^{2} (m - 1)^{2}

= (m + 1)^{2} (m - 1)^{2} (m + 7)

4 e^{- 0.65 \cdot 1}

(3 x^{2}) (5 x)

(8 t^{8}) (10 t^{6}) 4 t^{9}

e^{- t} e^{t}

1.5 \cdot 1 0^{- 3} \cdot 30

What is (m+1)^2(m-1)^2(m+7) ?
The solution to (m+1)^2(m-1)^2(m+7) is (m+1)^2(m-1)^2(m+7)