What is (7.8*10^{-19})(3712) ?

The solution to (7.8*10^{-19})(3712) is (1131)/(5^{20)*4096}

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simplify (7.8*10^{-19})(3712)

simplify

(7.8 \cdot 1 0^{- 19}) (3712)

\frac{1131}{5 ^{20} \cdot 4096}

Decimal Notation

2.89536 E - 15

Solution steps

(7.8 \cdot 1 0^{- 19}) (3712)

Apply rule:

(a) = a

(3712) = 3712

= 7.8 \cdot 1 0^{- 19} \cdot 3712

Multiply the numbers:

7.8 \cdot 3712 = 28953.6

= 28953.6 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 28953.6

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 28953.6

\frac{1}{1 0 ^{19}} \cdot 28953.6 = \frac{28953.6}{1 0 ^{19}}

= \frac{28953.6}{1 0 ^{19}}

\frac{28953.6}{1 0 ^{19}} = \frac{289536}{10 \cdot 1 0 ^{19}}

= \frac{289536}{10 \cdot 1 0 ^{19}}

10 \cdot 1 0^{19} = 1 0^{20}

= \frac{289536}{1 0 ^{20}}

Factor

289536 : 2^{8} \cdot 1131

= \frac{2 ^{8} \cdot 1131}{1 0 ^{20}}

Factor

1 0^{20} : 2^{20} \cdot 5^{20}

= \frac{2 ^{8} \cdot 1131}{2 ^{20} \cdot 5 ^{20}}

\frac{2 ^{8}}{2 ^{20}} = \frac{1}{2 ^{12}}

= \frac{1131}{2 ^{12} \cdot 5 ^{20}}

2^{12} = 4096

= \frac{1131}{5 ^{20} \cdot 4096}

- 2 u^{3} \cdot (4 u^{6})

9.3504700000000 \dots \cdot 1 0^{- 7}

3.21 \cdot 1 0^{- 16} \cdot 9.8049

2^{- 1074}

What is (7.8*10^{-19})(3712) ?
The solution to (7.8*10^{-19})(3712) is (1131)/(5^{20)*4096}