What is simplify-log_{10}(1.9)*10^{-19} ?

The solution to simplify-log_{10}(1.9)*10^{-19} is -log_{10}(19^{1/(10^{19)}})+1/(10^{19)}

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simplify-log_{10}(1.9)*10^{-19}

simplify

- lo g_{10} (1.9) \cdot 1 0^{- 19}

- lo g_{10} (1 9^{\frac{1}{1 0 ^{19}}}) + \frac{1}{1 0 ^{19}}

Decimal Notation

0

Solution steps

- lo g_{10} (1.9) \cdot 1 0^{- 19}

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

1 0^{- 19} lo g_{10} (1.9) = lo g_{10} (1. 9^{1 0^{- 19}})

= - lo g_{10} (1. 9^{1 0^{- 19}})

Simplify

= - \frac{1}{1 0 ^{19}} lo g_{10} (\frac{19}{10})

Simplify

lo g_{10} (\frac{19}{10}) : lo g_{10} (19) - 1

= - \frac{1}{1 0 ^{19}} (lo g_{10} (19) - 1)

Expand

- \frac{1}{1 0 ^{19}} (lo g_{10} (19) - 1) : - lo g_{10} (1 9^{\frac{1}{1 0 ^{19}}}) + \frac{1}{1 0 ^{19}}

= - lo g_{10} (1 9^{\frac{1}{1 0 ^{19}}}) + \frac{1}{1 0 ^{19}}

\frac{( e ^{x} )}{e ^{1 + x}}

100 e^{(- 5.0765 x 1 0^{- 3})} x^{24}

21 (0.5) L^{- 0.5} K^{0.5}

1.26 \cdot 1 0^{- 13}

2 e^{x} \cdot 2 e^{- x}

What is simplify-log_{10}(1.9)*10^{-19} ?
The solution to simplify-log_{10}(1.9)*10^{-19} is -log_{10}(19^{1/(10^{19)}})+1/(10^{19)}