What are the solutions to the equation -4x^2+6x+2=0 ?

The solutions to the equation -4x^2+6x+2=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4

Find the zeros of -4x^2+6x+2=0

The zeros of -4x^2+6x+2=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4

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- 4 x^{2} + 6 x + 2 = 0

x = - \frac{- 3 + 17}{4}, x = \frac{3 + 17}{4}

Decimal Notation

x = - 0.28077 \dots, x = 1.78077 \dots

Solution steps

- 4 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

6^{2} - 4 (- 4) \cdot 2 = 217

x_{1, 2} = \frac{- 6 \pm 2 17}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 17}{2 ( - 4 )}, x_{2} = \frac{- 6 - 2 17}{2 ( - 4 )}

x = \frac{- 6 + 2 17}{2 ( - 4 )} : - \frac{- 3 + 17}{4}

x = \frac{- 6 - 2 17}{2 ( - 4 )} : \frac{3 + 17}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 17}{4}, x = \frac{3 + 17}{4}

\frac{25 x ^{3} y}{125 x ^{3} y ^{2}}

7^{2} + 2 4^{2}

- x^{2} + x - 7 = 0

- 2.4 (3) + 9.6

\frac{n}{10} + 6 = 15

What are the solutions to the equation -4x^2+6x+2=0 ?
The solutions to the equation -4x^2+6x+2=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4
Find the zeros of -4x^2+6x+2=0
The zeros of -4x^2+6x+2=0 are x=-(-3+sqrt(17))/4 ,x=(3+sqrt(17))/4