What is the f(x)=cos^{-1/2}(x) ?

The f(x)=cos^{-1/2}(x) is Parity: Neither even nor odd Inverse: arccos(1/(x^2))

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f(x)=cos^{-1/2}(x)

f (x) = cos^{- \frac{1}{2}} (x)

Parity : Neither even nor odd

Inverse : arccos (\frac{1}{x ^{2}})

Solution steps

Parity of

cos^{- \frac{1}{2}} (x) :

Neither even nor odd

Inverse of

cos^{- \frac{1}{2}} (x) : arccos (\frac{1}{x ^{2}})

(43)^{2}

e^{jπ} e^{j \frac{π}{2}}

2.1 (4 π \cdot 1 0^{- 7})

y^{2} (e^{x} - e^{- x})^{2}

e^{- 75.75 (π)}

What is the f(x)=cos^{-1/2}(x) ?
The f(x)=cos^{-1/2}(x) is Parity: Neither even nor odd<br/>Inverse: arccos(1/(x^2))