What is a^{2/5}cdota^{-3} ?

The solution to a^{2/5}cdota^{-3} is (ctdo)/(a^{13/5)}

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simplify a^{2/5}cdota^{-3}

simplify

a^{\frac{2}{5}} c d o t a^{- 3}

\frac{c t d o}{a ^{\frac{13}{5}}}

Solution steps

a^{\frac{2}{5}} c d o t a^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= c a^{\frac{2}{5}} \frac{1}{a ^{3}} t d o

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot a ^{\frac{2}{5}} c d o t}{a ^{3}}

Multiply:

1 \cdot a^{\frac{2}{5}} = a^{\frac{2}{5}}

= \frac{c a ^{\frac{2}{5}} t d o}{a ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{a ^{\frac{2}{5}}}{a ^{3}} = \frac{1}{a ^{3 - \frac{2}{5}}}

= \frac{c t d o}{a ^{3 - \frac{2}{5}}}

Subtract the numbers:

3 - \frac{2}{5} = \frac{13}{5}

= \frac{c t d o}{a ^{\frac{13}{5}}}

4 e^{5 x} \cdot e^{- 5 x}

7.13 \cdot 1 0^{- 7}

\frac{e ^{x}}{( e ^{x} ) ^{x}}

8^{- 7} 0. 8^{5}

10 e^{- 3} \cdot 5 e

What is a^{2/5}cdota^{-3} ?
The solution to a^{2/5}cdota^{-3} is (ctdo)/(a^{13/5)}