What is e^{-0.3x}(cos(x)+sin(x)) ?

The solution to e^{-0.3x}(cos(x)+sin(x)) is (cos(x)+sin(x))/(e^{0.3x)}

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simplify e^{-0.3x}(cos(x)+sin(x))

simplify

e^{- 0.3 x} (cos (x) + sin (x))

\frac{cos ( x ) + sin ( x )}{e ^{0.3 x}}

Solution steps

e^{- 0.3 x} (cos (x) + sin (x))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{0.3 x}} (cos (x) + sin (x))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( cos ( x ) + sin ( x ) )}{e ^{0.3 x}}

1 \cdot (cos (x) + sin (x)) = cos (x) + sin (x)

= \frac{cos ( x ) + sin ( x )}{e ^{0.3 x}}

e^{- 5 t} sinh (6 t)

(2.7 \cdot 1 0^{- 6}) \cdot 1 0^{9}

6.6 (10)^{- 6} (50) (5)

22598377 \cdot e^{- 12}

7.21 \cdot 1 0^{- 3}

What is e^{-0.3x}(cos(x)+sin(x)) ?
The solution to e^{-0.3x}(cos(x)+sin(x)) is (cos(x)+sin(x))/(e^{0.3x)}