What is e^{-1}(1/5 e^{5x+1}+C) ?

The solution to e^{-1}(1/5 e^{5x+1}+C) is 1/e (C+1/5 e^{5x+1})

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simplify e^{-1}(1/5 e^{5x+1}+C)

simplify

e^{- 1} (\frac{1}{5} e^{5 x + 1} + C)

\frac{1}{e} (C + \frac{1}{5} e^{5 x + 1})

Solution steps

e^{- 1} (\frac{1}{5} e^{5 x + 1} + C)

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{e} (C + \frac{1}{5} e^{5 x + 1})

A^{N} B^{N}

\frac{e ^{t^{4}}}{e ^{t^{2}}}

e^{- x} x (2 - x)

7.21 \cdot 1 0^{- 2}

x \cdot x^{2} e^{x}

What is e^{-1}(1/5 e^{5x+1}+C) ?
The solution to e^{-1}(1/5 e^{5x+1}+C) is 1/e (C+1/5 e^{5x+1})