What are the solutions to the equation x^2-12x+10=-2x^2+1 ?

The solutions to the equation x^2-12x+10=-2x^2+1 are x=3,x=1

Find the zeros of x^2-12x+10=-2x^2+1

The zeros of x^2-12x+10=-2x^2+1 are x=3,x=1

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x^{2} - 12 x + 10 = - 2 x^{2} + 1

x = 3, x = 1

Solution steps

x^{2} - 12 x + 10 = - 2 x^{2} + 1

Move

1

to the left side

x^{2} - 12 x + 9 = - 2 x^{2}

Move

2 x^{2}

to the left side

3 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 \cdot 9 = 6

x_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6}{2 \cdot 3} : 3

x = \frac{- ( - 12 ) - 6}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

\frac{5 ^{2}}{5 ^{2}}

\frac{1}{24} x - \frac{5}{8} = \frac{2}{3}

\frac{5 π}{4} + \frac{π}{4}

x^{2} - 8 x - 22 = - 10

42 = - 7 (z - 3)

What are the solutions to the equation x^2-12x+10=-2x^2+1 ?
The solutions to the equation x^2-12x+10=-2x^2+1 are x=3,x=1
Find the zeros of x^2-12x+10=-2x^2+1
The zeros of x^2-12x+10=-2x^2+1 are x=3,x=1