What is (4*(-2))^2resolver ?

The solution to (4*(-2))^2resolver is 64e^2lr^2sov

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simplify (4*(-2))^2resolver

simplify

(4 \cdot (- 2))^{2} reso l v er

64 e^{2} l r^{2} so v

Solution steps

(4 (- 2))^{2} reso l v er

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= (4 (- 2))^{2} rso l v e^{1 + 1} r

Add the numbers:

1 + 1 = 2

= (4 (- 2))^{2} rso l v e^{2} r

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

rr = r^{1 + 1}

= (4 (- 2))^{2} so l v e^{2} r^{1 + 1}

Add the numbers:

1 + 1 = 2

= (4 (- 2))^{2} so l v e^{2} r^{2}

Remove parentheses:

(- a) = - a

= (- 4 \cdot 2)^{2} so l v e^{2} r^{2}

(- 4 \cdot 2)^{2} = 8^{2}

= 8^{2} e^{2} l r^{2} so v

8^{2} = 64

= 64 e^{2} l r^{2} so v

2.51 \cdot 1 0^{- 7} \cdot 50

- 5 x^{3} (4 x^{2})

- \frac{1}{2} x^{- 2} \cdot ln (x)

(x - 5 y + 2)^{2} \cdot (x + 5 y - 2)^{2}