What is (1.08*10^{-11})(55) ?

The solution to (1.08*10^{-11})(55) is 297/500000000000

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simplify (1.08*10^{-11})(55)

simplify

(1.08 \cdot 1 0^{- 11}) (55)

\frac{297}{500000000000}

Decimal Notation

5.94 E - 10

Solution steps

(1.08 \cdot 1 0^{- 11}) (55)

Apply rule:

(a) = a

(55) = 55

= 1.08 \cdot 1 0^{- 11} \cdot 55

Multiply the numbers:

1.08 \cdot 55 = 59.4

= 59.4 \cdot 1 0^{- 11}

= 1 0^{- 11} \cdot 59.4

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 11} = \frac{1}{1 0 ^{11}}

= \frac{1}{1 0 ^{11}} \cdot 59.4

\frac{1}{1 0 ^{11}} \cdot 59.4 = \frac{59.4}{1 0 ^{11}}

= \frac{59.4}{1 0 ^{11}}

\frac{59.4}{1 0 ^{11}} = \frac{594}{10 \cdot 1 0 ^{11}}

= \frac{594}{10 \cdot 1 0 ^{11}}

10 \cdot 1 0^{11} = 1 0^{12}

= \frac{594}{1 0 ^{12}}

Factor the number:

594 = 2 \cdot 297

= \frac{2 \cdot 297}{1 0 ^{12}}

Factor

1 0^{12} : 2^{12} \cdot 5^{12}

= \frac{2 \cdot 297}{2 ^{12} \cdot 5 ^{12}}

\frac{2}{2 ^{12}} = \frac{1}{2 ^{11}}

= \frac{297}{2 ^{11} \cdot 5 ^{12}}

2^{11} \cdot 5^{12} = 500000000000

= \frac{297}{500000000000}

2 e^{x} \cdot 2 x

(n + 1)^{- 1}

(9. 1^{9})^{2} 0.9 1^{- 6}

\frac{1 ^{2}}{2.5 7 ^{2}}

What is (1.08*10^{-11})(55) ?
The solution to (1.08*10^{-11})(55) is 297/500000000000