What is expand (1-1/2 x)^{-1} ?

The solution to expand (1-1/2 x)^{-1} is 2/(-x+2)

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expand (1-1/2 x)^{-1}

expand

(1 - \frac{1}{2} x)^{- 1}

\frac{2}{- x + 2}

Solution steps

(1 - \frac{1}{2} x)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( 1 - \frac{1}{2} x )}

\frac{1}{2} x = \frac{x}{2}

= \frac{1}{1 - \frac{x}{2}}

Join

1 - \frac{x}{2} : \frac{2 - x}{2}

= \frac{1}{\frac{2 - x}{2}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{2 - x}

9.419 \cdot 1 0^{- 5}

e^{- 2 s} ln (\frac{s}{s - 1})

3.271 \cdot 1 0^{- 22}

300 \cdot 8.62 \cdot 1 0^{- 5}

256 x^{2} y^{2}

What is expand (1-1/2 x)^{-1} ?
The solution to expand (1-1/2 x)^{-1} is 2/(-x+2)