What are the solutions to the equation x^2-6x+9=49 ?

The solutions to the equation x^2-6x+9=49 are x=10,x=-4

Find the zeros of x^2-6x+9=49

The zeros of x^2-6x+9=49 are x=10,x=-4

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x^{2} - 6 x + 9 = 49

x = 10, x = - 4

Solution steps

x^{2} - 6 x + 9 = 49

Move

49

to the left side

x^{2} - 6 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 40) = 14

x_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 1}

x = \frac{- ( - 6 ) + 14}{2 \cdot 1} : 10

x = \frac{- ( - 6 ) - 14}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 10, x = - 4

4 + \frac{65 - 64}{48}

(\frac{1}{6})^{3}

\frac{30 x ^{4} y ^{5}}{20 x ^{5} y ^{2}}

5 \cdot (a + 3) 2 - (a + 3)

x (x - 16) = 0

What are the solutions to the equation x^2-6x+9=49 ?
The solutions to the equation x^2-6x+9=49 are x=10,x=-4
Find the zeros of x^2-6x+9=49
The zeros of x^2-6x+9=49 are x=10,x=-4