What are the solutions to the equation 8*x^2-(-1/4)= 33/4 ?

The solutions to the equation 8*x^2-(-1/4)= 33/4 are x=1,x=-1

Find the zeros of 8*x^2-(-1/4)= 33/4

The zeros of 8*x^2-(-1/4)= 33/4 are x=1,x=-1

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8 \cdot x^{2} - (- \frac{1}{4}) = \frac{33}{4}

x = 1, x = - 1

Solution steps

8 x^{2} - (- \frac{1}{4}) = \frac{33}{4}

Refine

8 x^{2} + \frac{1}{4} = \frac{33}{4}

Move

\frac{1}{4}

to the right side

8 x^{2} = \frac{33}{4} - \frac{1}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

8 x^{2} = \frac{33 - 1}{4}

Subtract the numbers:

33 - 1 = 32

8 x^{2} = \frac{32}{4}

Divide the numbers:

\frac{32}{4} = 8

8 x^{2} = 8

Divide both sides by

8

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

- ∣ 3 + 3 x ∣ + 8 < - 4

- 2 (k + 3) = 0

x^{2} + x < 12

- 13 x - 7 = 3 x + 233

20 > - 2 x - 4

What are the solutions to the equation 8*x^2-(-1/4)= 33/4 ?
The solutions to the equation 8*x^2-(-1/4)= 33/4 are x=1,x=-1
Find the zeros of 8*x^2-(-1/4)= 33/4
The zeros of 8*x^2-(-1/4)= 33/4 are x=1,x=-1