What is (9.2x10^5)*(4x10^{-3}) ?

The solution to (9.2x10^5)*(4x10^{-3}) is 3680x^2

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simplify (9.2x10^5)*(4x10^{-3})

simplify

(9.2 x 1 0^{5}) \cdot (4 x 1 0^{- 3})

3680 x^{2}

Solution steps

(9.2 x \cdot 1 0^{5}) (4 x \cdot 1 0^{- 3})

Simplify

4 x \cdot 1 0^{- 3} : \frac{x}{250}

= 9.2 x \cdot 1 0^{5} \cdot \frac{x}{250}

9.2 = \frac{46}{5}

= \frac{46}{5} x \cdot 1 0^{5} \cdot \frac{x}{250}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{46 x \cdot 1 0 ^{5} x}{5 \cdot 250}

Multiply the numbers:

5 \cdot 250 = 1250

= \frac{46 x \cdot 1 0 ^{5} x}{1250}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{46 x ^{2} \cdot 1 0 ^{5}}{1250}

Factor the number:

46 = 2 \cdot 23

= \frac{2 \cdot 23 x ^{2} \cdot 1 0 ^{5}}{1250}

Factor the number:

1250 = 2 \cdot 625

= \frac{2 \cdot 23 x ^{2} \cdot 1 0 ^{5}}{2 \cdot 625}

Cancel the common factor:

2

= \frac{23 x ^{2} \cdot 1 0 ^{5}}{625}

Factor

1 0^{5} : 5^{5} \cdot 2^{5}

= \frac{23 x ^{2} \cdot 5 ^{5} \cdot 2 ^{5}}{625}

Factor the number:

625 = 5^{4}

= \frac{23 x ^{2} \cdot 5 ^{5} \cdot 2 ^{5}}{5 ^{4}}

\frac{5 ^{5}}{5 ^{4}} = 5

= 23 x^{2} \cdot 5 \cdot 2^{5}

Multiply the numbers:

23 \cdot 5 = 115

= 115 x^{2} \cdot 2^{5}

= 2^{5} \cdot 115 x^{2}

2^{5} = 32

= 32 \cdot 115 x^{2}

Multiply the numbers:

32 \cdot 115 = 3680

= 3680 x^{2}

e^{- 2 l n (4 + 15)}

x^{4} \cdot x \cdot e^{x}

(7 f^{4}) (8 f^{3})

e^{- x} e^{c}

What is (9.2x10^5)*(4x10^{-3}) ?
The solution to (9.2x10^5)*(4x10^{-3}) is 3680x^2